Pseudo Code for Circle Calculations

Problem Statement

Compute the area and circumference of a circle based on the radius r:

• If r >= 1.0, calculate both area and circumference.
• If r < 1.0, calculate only the circumference.

Constants

• Define the value of π (Pi) as a constant value, e.g., PI = 3.14159.

Variables

• Input: r (radius)
• Calculation: area, circumference

Pseudo Code

FUNCTION CalculateCircleProperties(r)
    // Define constant for Pi
    CONSTANT PI = 3.14159
    
    // Initialize variables
    DECLARE area AS FLOAT
    DECLARE circumference AS FLOAT
    
    // Calculate circumference
    circumference = 2 * PI * r
    
    // Check if radius is greater than or equal to 1.0
    IF r >= 1.0 THEN
        // Calculate area
        area = PI * (r * r)
        // Print area and circumference
        PRINT "Area: " + area
        PRINT "Circumference: " + circumference
    ELSE
        // Print only circumference
        PRINT "Circumference: " + circumference
    ENDIF
END FUNCTION

Explanation of Steps

1. Define Pi: A constant value for π is established.
2. Declare Variables: Space for area and circumference is allocated.
3. Calculate Circumference: The circumference is calculated using the formula C = 2 * π * r.
4. Conditional Check for Radius:
   • If the radius is greater than or equal to 1.0, calculate the area using A = π * r^2 and print both area and circumference.
   • If the radius is less than 1.0, print only the circumference.

This structured approach allows for clear and effective calculation of circle properties based on the radius input.