AI Big-O Analyzer
Complexity Analysis of the `summaryRanges` Function
This document analyzes the `summaryRanges` function in Swift, detailing its time and space complexity as O(n). It explains initial checks, the main loop's operations, and provides an input scenario to illustrate average-case behavior.
Prompt
Answer
Complexity Analysis of summaryRanges
Function
The provided function summaryRanges
is designed to take an array of integers and return a list of ranges represented as strings. The analysis of its time and space complexity will be presented below.
Code Overview
Language
Swift
Function Definition
func summaryRanges(_ nums: [Int]) -> [String] {
var result: [String] = []
var str = ""
var left = 0
var right = 1
if nums.isEmpty {
return []
}
if nums.count == 1 {
return ["\(nums[left])"]
}
while right < nums.count {
if nums[right] - nums[left] != 1 {
if str.isEmpty {
result.append("\(nums[left])")
} else {
str.append("->\(nums[left])")
result.append(str)
str = ""
}
} else if str.isEmpty {
str.append("\(nums[left])")
}
left += 1
right += 1
}
if str.isEmpty {
result.append("\(nums[left])")
} else {
str.append("->\(nums[left])")
result.append(str)
}
return result
}
Time Complexity Analysis
Initial Checks:
- The function checks if
nums
is empty or contains a single element, which takes constant time, O(1).
- The function checks if
Main Loop:
- The while loop runs as long as
right < nums.count
. In the worst case, this iterates through the entire input array, namely O(n), wheren
is the length ofnums
. - Within the loop:
- The condition checks (
nums[right] - nums[left]
) and string manipulations (appending tostr
andresult
) are executed in constant time, i.e., O(1).
- The condition checks (
- The while loop runs as long as
Final Append:
- After the loop concludes, a final check is made to append the last range or singular number, which also takes constant time, O(1).
Overall Time Complexity
Thus, the overall time complexity for the summaryRanges
function is O(n), where n is the length of the input array nums
.
Space Complexity Analysis
Result Array:
- The space complexity for storing the
result
array depends on the number of ranges being generated. In the worst case, all numbers are non-consecutive (e.g.,[1, 3, 5]
), resulting in O(n) space.
- The space complexity for storing the
String Storage:
- The temporary string
str
holds concatenated ranges and can also take up O(n) space in the worst case if all elements form individual ranges.
- The temporary string
Overall Space Complexity
Consequently, the space complexity is O(n), where n is the length of the input array nums
.
Scenario Illustrating Average-Case Behavior
Input Scenario: Consider an input array like [0, 1, 2, 4, 5, 7]
.
- In this scenario, the ranges formed would be
[0->2]
and[4->5]
with the single number[7]
. - The algorithm will handle small consecutive sequences efficiently before encountering gaps.
Expected Runtime and Memory Usage
- Runtime: The average-case behavior would still ensure a single pass through the array, maintaining O(n) runtime.
- Memory Usage: It would similarly involve storing a few ranges, still leading to O(n) memory use as the maximum number of unique elements forming ranges is proportional to the size of the input.
In conclusion, the summaryRanges
function is efficient with a linear time and space complexity relative to the size of the input. This makes it suitable for handling relatively larger datasets, provided they are always narrow integers. For advanced insights into performance and optimizing data handling, consider exploring further resources on the Enterprise DNA Platform.
Description
This document analyzes the summaryRanges
function in Swift, detailing its time and space complexity as O(n). It explains initial checks, the main loop's operations, and provides an input scenario to illustrate average-case behavior.