Prompt
Answer
Sum of Even Numbers from 0 to 1000 in C++
This document outlines a simple C++ function that calculates the sum of even numbers from 0 to 1000. The implementation includes input validation, documentation, and usage examples to ensure clarity and best practices.
Code Implementation
#include
/// @brief Calculates the sum of even numbers from 0 to a specified limit.
/// @param limit The upper limit up to which even numbers are summed. Must be non-negative.
/// @return The sum of even numbers from 0 to the limit.
/// @exception std::invalid_argument if the provided limit is negative.
int sumEvenNumbers(int limit) {
// Validate input
if (limit < 0) {
throw std::invalid_argument("Limit must be non-negative.");
}
int sum = 0; // Initialize sum variable
// Iterate through numbers from 0 to limit
for (int i = 0; i <= limit; i += 2) { // Increment by 2 for even numbers
sum += i; // Add even number to sum
}
return sum; // Return the final sum
}
int main() {
// Define the upper limit
int limit = 1000;
// Calculate the sum of even numbers from 0 to limit
try {
int result = sumEvenNumbers(limit);
// Output the result
std::cout << "The sum of even numbers from 0 to " << limit << " is: " << result << std::endl;
} catch (const std::invalid_argument& e) {
std::cerr << e.what() << std::endl; // Handle invalid argument exception
}
return 0; // Indicate successful execution
}
Explanation of the Code
Imports: We include the
<iostream>
library for input and output operations.Function Documentation:
- The
sumEvenNumbers
function is documented with a clear description of its purpose, parameters, return type, and exceptions.
- The
Input Validation:
- The function checks if the provided
limit
is negative, raising anstd::invalid_argument
exception if so.
- The function checks if the provided
Summation Logic:
- A simple for-loop iterates from 0 to the
limit
, adding every even number (incrementing by 2) to the sum.
- A simple for-loop iterates from 0 to the
Main Function:
- Sets the limit to 1000 and calls the summation function.
- Handles any exceptions by printing an error message to the console.
Usage Example
This code can be compiled and run in a C++ environment. When executed, it will output:
The sum of even numbers from 0 to 1000 is: 250500
Conclusion
This implementation is efficient and straightforward, demonstrating best practices in input validation, modular programming, and clear documentation that allows for easy future modifications. For further development and best practices in data science and coding, consider exploring courses on the Enterprise DNA Platform.
Description
This document presents a C++ function to compute the sum of even numbers from 0 to 1000, featuring input validation, thorough documentation, and clear usage examples for best coding practices.