Prompt
def recursive_fibonacci(n):
if n <= 1:
return n
else:
return recursive_fibonacci(n-1) + recursive_fibonacci(n-2)
num_terms = 10
for i in range(num_terms):
print(recursive_fibonacci(i))
Answer
Simplified and Minified Python Code
def fib(n):
return n if n <= 1 else fib(n-1) + fib(n-2)
num = 10
[print(fib(i)) for i in range(num)]
Comments
- The
recursive_fibonacci
function is refactored tofib
for simplicity. - The code logic remains the same, calculating the Fibonacci sequence.
- The
for
loop for printing the Fibonacci numbers is replaced with a list comprehension.
Test Case
- Input:
num = 10
- Expected Output:
0 1 1 2 3 5 8 13 21 34
- Actual Output: Same as expected output
Description
The Python code features a refined and minified implementation of the Fibonacci sequence calculation using recursion, with a compact print statement for a specified range of numbers.
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