Prompt
def fibonacci(n):
if n <= 1:
return n
else:
return fibonacci(n-1) + fibonacci(n-2)
for i in range(10):
print(fibonacci(i))
Answer
Python Code Visualization using DOT Notation
digraph {
rankdir=LR;
node [shape=box];
Fibonacci -> Base_Case;
Fibonacci -> Recursive_Call;
Recursive_Call -> Fibonacci;
Recursive_Call -> Fibonacci;
Base_Case [shape=diamond];
Base_Case -> return_n;
return_n [shape=Mdiamond];
Fibonacci_Call -> Fibonacci;
Fibonacci_Call -> Fibonacci;
for_loop -> range;
range -> i;
for_loop -> print;
print -> fibonacci_call;
fibonacci_call -> i;
}
Main Points:
- The visualization depicts the structure of a Fibonacci function implemented in Python.
- The function involves recursion to calculate the Fibonacci sequence.
- The function has a base case when
n
is less than or equal to 1. - The recursive step involves calling the
fibonacci
function withn-1
andn-2
. - The code includes a loop that iterates over the range of 0 to 9 and prints the result of the Fibonacci sequence at each iteration.
Description
Visual representation of a Python Fibonacci function showcasing recursion, base case, and looping structure for calculating the Fibonacci sequence.
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